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  • Parsing file to retrieve specific pattern

    I have a txt file with several rows. Each row contains several words separated by space. I want to print the values which have pattern like amenXXXXXXX (where length of X string is different in many rows). I tried grep with -o option and some other one-liners but not able to print only the words that have the pattern like amen. Indeed I want the output like:

    amen2wit
    amen3grps
    amen0qw
    amen8dbskm.....

    I will appreciate your expert suggestions.

  • #2
    Are all amenXXXXXXX in the same column? If yes, you could just:

    cut -f N

    Where N is the column number.
    savetherhino.org

    Comment


    • #3
      Originally posted by Shishir View Post
      I have a txt file with several rows. Each row contains several words separated by space. I want to print the values which have pattern like amenXXXXXXX (where length of X string is different in many rows). I tried grep with -o option and some other one-liners but not able to print only the words that have the pattern like amen. Indeed I want the output like:

      amen2wit
      amen3grps
      amen0qw
      amen8dbskm.....

      I will appreciate your expert suggestions.
      What about this:

      Code:
      echo "no pattern
      amen
      amenXXX
      foo amenBLA foo2
      etc" > mytext.txt
      
      grep -o 'amen[^ ]*' mytext.txt
      amen
      amenXXX
      amenBLA
      How do you want to deal with the pattern occurring more than once per row, if that happens?

      Comment


      • #4
        Thanks you all !!

        Originally posted by dariober View Post
        What about this:

        Code:
        echo "no pattern
        amen
        amenXXX
        foo amenBLA foo2
        etc" > mytext.txt
        
        grep -o 'amen[^ ]*' mytext.txt
        amen
        amenXXX
        amenBLA
        How do you want to deal with the pattern occurring more than once per row, if that happens?

        Comment

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