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  • Float Arithmatic in Bash

    Hi,
    I have to use this code below which works fine :

    output=$path
    tmp_dir=$path1
    mu=200
    sigma=80
    output_dir=$output
    tmp_dir=$tmp
    mu_length=$mu
    sigma_length=$sigma
    echo "input_format=sam
    sv_type=all
    mates_orientation=RF
    read1_length=100
    read2_length=100
    output_dir=$output
    tmp_dir=$tmp
    mu_length=$mu
    sigma_length=$sigma
    window_size=$((sigma*2 + mu*2))" > abc.txt


    What I need to do is
    window_size=$((sigma*2.82 + mu*2)) # float multiplication

    Will this thing work :
    window_size=$(('scale=4; sigma*2.82 + mu*2' | bc))

    Or any other way by which I can do float multiplication.

    Thanks in advance for the help

  • #2
    Originally posted by vishal.rossi View Post
    Will this thing work :
    window_size=$(('scale=4; sigma*2.82 + mu*2' | bc))
    Something like that should work. Bash doesn't do floating point arithmetic by itself. Honestly, you'll find if more convenient to anything more complicated in another language (perl, python, whatever). Shell scripts are great for simple process control jobs, but I wouldn't want to write anything else using them.

    Comment


    • #3
      Try this
      window_size=`echo "sigma*2.82+mu*2" | bc`
      echo $window_size

      or

      window_size=`echo "scale=4;$sigma*2.82+$mu*2" | bc`

      See : http://stackoverflow.com/questions/1...-expr-on-float
      Last edited by Richard Finney; 05-04-2013, 08:46 AM.

      Comment


      • #4
        Thanks for the reply. I too figured out a way:

        window_size=$(echo $d_mu*2 + $e_sigma*2.82 | bc -l)
        step_length=$(echo $d_mu*2/4 + $e_sigma*2.82/4 | bc -l)

        Comment

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