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Old 09-14-2010, 09:26 AM   #1
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Location: New York

Join Date: Sep 2010
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Default Setting up and efficiency

I am hoping to set up ChIP-Seq in our lab. I was wondering if someone could help me answer a few questions and direct me to the right literature as what i have read so far is quite discrepant from each other.

How many cells would I typically I need for a ChIP-Seq experiment looking at one transcription factor binding site through the genome. I have read anything between 300,000 to 1x10^8.

Secondly, is there a relationship between the amount of chromatin used and the number of reads you get from an experiment. From the single IP experiments I have been doing, I could then perhaps estimate how much material i would need to get 20-30 million reads.

ColNYC is offline   Reply With Quote

cell number, chromatin amount, efficiency, reads

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