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Thread | Thread Starter | Forum | Replies | Last Post |
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#1 |
Junior Member
Location: China Join Date: Oct 2010
Posts: 3
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Recently, i faced with a problem, I want to overlap the sequences in order to have a longer one, but i can't find out a assembler which could be suitable to my data.
The length of my data is wide range, from 102bp to 87249bp, with N50 length of 738bp, so it count not be assembled using 454 data assembler, such as Newbler. What's more, the total bases number of my data is about 1.9G, so it seems to be impossible to use Sanger data assembler. What i want to do is to extend the sequences based on the overlap relationship between them, if someone have any suggestion, please inform me. thank you |
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#2 |
Member
Location: Uppsala Join Date: Jan 2010
Posts: 25
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hello,
I also want to do the same but could not find any software. Did you find any overlaping assembler?
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~Adnan~ |
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#3 |
Senior Member
Location: Berlin, DE Join Date: May 2008
Posts: 628
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Have a look at Celera Assembler, http://sourceforge.net/apps/mediawik...itle=Main_Page
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#4 |
Junior Member
Location: Italy Join Date: Sep 2012
Posts: 4
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Hello,
I used Pear to merge my Illumina (MiSeq sequencer) pair-end reads. I'd like to know the overlap length in each of the merged reads in order to calculate min length, max, average, mode, median etc... Can you suggest my how to do? I tried with a perl script (length R1 + length R2 - length MergedR1R2) but I am not very good in programming.... Can anybody help me and tell me how to do this? Thanks!! |
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#5 |
Senior Member
Location: Boston area Join Date: Nov 2007
Posts: 747
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#!/usr/bin/perl #!/usr/bin/perl # debugging left as exercise for student :-) use strict; foreach my $arg(@ARGV) { my %lengths=(); # read sequence file for lengths my $rdr=new Bio::SeqIO(-file=>$arg,-format=>'fastq'); my $sum=0; my $cnt=0; while (my $rec=$rdr->next_seq) { $lengths{$rec->length}++; $sum+=$rec->length; $cnt++; } my @sortedLengths=sort {$a<=>$b} keys %lengths; my $minLen=$sortedLengths[0]; my $maxLen=$sortedLengths[$#sortedLengths]; my $meanLen=$sum/$cnt; my ($modeLen)=sort {$lengths{$b}<=>$lengths{$a}} keys %lengths; my $medLen="error"; # calculating median left as exercise print join("\t",$arg,$minLen,$maxLen,$meanLen,$modeLen,$medLen),"\n"; } |
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#6 |
Junior Member
Location: Italy Join Date: Sep 2012
Posts: 4
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Thank you very much!
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overlap |
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