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  • Regex Searches?

    Hello,

    I've been at this problem for some time now and any adice would be great. I have a file as such: Peter..Bjorn,John..Mary,Paul..Simon,Jack..Steve,

    I wrote the following code:
    @array = $line =~ /([A-Za-z]+\.\.[A-Za-z]+\,[A-Za-z]+\.\.[A-Za-z]+)/g;

    It gives me: Peter,..Bjorn,John..Mary Paul..Simon,Jack..Steve

    What I really want it to give me is: Peter..Bjorn,John..Mary John..Mary,Paul..Simon Paul..SImon,Jack..Steve

    Is there anyway to go about doing that? I tried a lookaround, but that didn't help much.

    Thanks
    Last edited by anzdro; 07-18-2013, 11:04 AM.

  • #2
    More compact regex are more readable; use /gi; and you can drop the extra a-z (i=ignore case)

    Could you check your examples for typos -- that regex should NOT be generating the output you specify (your code is missing the join command anyhow that you must be referring to). And is it you just want the 2nd name pair duplicated? It would help if you underlined what is different between intended and obtained.

    Also, please use the CODE formatting for your example & code -- much, MUCH easier to debug regex when in constant width font
    Last edited by krobison; 07-18-2013, 12:37 PM.

    Comment


    • #3
      You want it to print out the first comma delimited bit, then print out two copies of each of the following comma delimited bits with a space between the copies, then print out a single copy of the last bit? That sounds difficult with a one-liner

      In Perl I would
      Code:
      #!/usr/bin/perl
      
      $current_line = "Peter..Bjorn,John..Mary,Paul..Simon,Jack..Steve,";
      @line = split(",",$current_line);
      print "$line[0],";
      for ($x = 1; $x < (@line - 1); $x++) {
       print "$line[$x] $line[$x],";
      }
      print "$line[$x]\n";
      I ran it and got Peter..Bjorn,John..Mary John..Mary,Paul..Simon Paul..Simon,Jack..Steve
      Providing nextRAD genotyping and PacBio sequencing services. http://snpsaurus.com

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