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  • Inconsistency with SAM flag output?

    Hi all.

    I'm very confused about the output that I'm getting here.

    Consider the below SAM output. These are the mapping results of a single read pair. You can see that the first read maps to chromosome 6 at 5007, and the second maps to 5149.

    However, the SAM flags suggest that the first read is the *second* in the pair, and that the second read is the *first* in the pair. Also, the first read maps to the forward strand, while the second read maps to the reverse strand.

    -----------------
    k_2_6_11305011 163 chr6 5007 0 75M * 0 217 ATATAACTGCGAGATTAATCTCAGACAATGACACAAAATATAGCGAAGTTGGTAAGTTATTTAGTAAAGCTCATG BBB;CBBC4)7B8B=-BB;B?BB?2*;BB-BBBBBBBB?C-;B-@>AC8=B909BB0@4<8-B;-=B0B@+;C--
    MF:i:18 AM:i:0 SM:i:0 NM:i:2 UQ:i:21 H0:i:0 H1:i:0

    k_2_6_11305011 83 chr6 5149 0 75M * 0 -217 TTTATCTTTCAACAACTTGTGTGTTATATTTTGGAATACAGATACAAAGTTATTATGCTTTCAAAATATTCTTTT ?BB?BBB?BB8BBB0=-=BBBBB?==BB?BBB?B=B?-0?BBB8B--B8BBBBB-C8C=?=BBBB8?BBBCB=8B
    MF:i:18 AM:i:0 SM:i:0 NM:i:0 UQ:i:0 H0:i:4 H1:i:0

    -----------------

    The SAM flags suggest that this pair is 'everted' (i.e. the first strand is reverse, while the second strand is forward). However this is not really the case.

    Am I interpreting this output correctly?

  • #2
    The read at 5007 has a flag of 163, which = 128+32+2+1 = second read, forward direction.
    The read at 5149 has a flag of 83, which = 64+16+2+1 = first read, reverse direction.

    That's a proper pair; the two ends point in towards each other. There's nothing wrong here.

    I'm not sure how you determined that the read at 5007 was read 1; does the sequence from the read1 fastq blat to 5007? Maybe there was a mix up in the order that the files were given to the software that did the alignment or made the .sam, because the only way to know from looking at the sam output alone which was the first read and which was the second is to look at the flags.

    Comment


    • #3
      My assumption was that the second read would be the one mapped to the more distal location.

      Per the output I provided, the "second" read is actually the one that comes first in mapping (at 5007). That's why I'm confused.

      Comment


      • #4
        the flag in sam file is really confusing to me as well.
        what is the meaning of "second read"? does it mean from the second fastq file?
        I am using tophat.

        Comment


        • #5
          Yes, the second read is the second fastq you give to your mapping software, from the reads originating at adaptor 2.

          It's not like the DNA molecules and the adaptor molecules know which end of the DNA is closer to what your reference has arbitrarily designtated the beginning of the DNA sequence. So of course there can't be a correlation between read 1 and the read closer to the beginning of your reference.

          Comment


          • #6
            See http://picard.sourceforge.net/explain-flags.html to help translate flags. Also check out the SAM spec for more explanations.

            Comment


            • #7
              if a pair is mapped into genome as below,
              -------> <-------
              read1 read2
              does it mean the pair is located in + strand?

              otherwise, if a pair is mapped into genome as below,
              -------> <-------
              read2 read1
              does it mean the pair is located in - strand?

              Comment


              • #8
                Originally posted by jay2008 View Post
                if a pair is mapped into genome as below,
                -------> <-------
                read1 read2
                does it mean the pair is located in + strand?

                otherwise, if a pair is mapped into genome as below,
                -------> <-------
                read2 read1
                does it mean the pair is located in - strand?
                This question makes no sense.

                The DNA that went onto the flow cell is double stranded. If your two reads overlapped perfectly, one would be a rev comp of the other, not the reverse.

                Comment

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